Hi,
Grade Distrubution for Homework-2 :
Grad | avg:87.4 | 96(H) | 74(L) |
| | | |
UG | avg:84.8 | 96(H) | 72(L) |
And marking scheme is as follows::
Total : 100 points
PART A:
1. 5
2. 6 (2+2+2)
3.
Part A: 4 (2+2)
Part B: 4
Part C: 8
4.
Part A: 3
Part B: 3
5. 4
PART B: (true or flase )
18 (3 X 6)
[CSP1]
i. 5
ii. 3
iii. 6
[CSP2]
1.1 6
1.2 4
1.3 4
Qn. II (Pattern DB Heuristics)
A.
A.1 2
A.2 2
A.3 3
A.4 5
B.
5
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And, first part of the CSP solution is missing from the solutions page on the course web-site. I am writing it down below:
[CSP1]
1.
Let Jobs be J1, J2, J3 and J4 and days are d1,d2,d3.
Domains: J1 = {d1,d2,d3}, J2 = {d1,d2,d3}, J3 = {d1,d2,d3}
Constraints as no-goods:
(J1>=J2), (J2>=J3 & J2>=J4), (J3=J2) (J3=J4), (|J4 - J1| < 1)
2. No its not binary. (There is a ternary constraint)
3.
Using forward checking and dynamic variable ordering:
path1 at root: pickup J2=d1, using forward checking J1={ } => this a FAIL case
path2 at root: pickup J2 = d2. [ D(J1) = {d1} D(J3)= {d1,d3} D(J4) = {d1,d2,d3} ]
--> Followed by J1=d1 [ D(J3) = {d1,d3} D(J4) = {d3} ]
--> Followed by J4=d3 [ (D(J3) = {d1} ]
--> Followed by J3=d1 --> all variables are exhausted with no contraints => SUCCESS
So, the assignment is { J1,J3 = d1 ; J2 = d2; J4 = d3 }
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Let me know if you have any questions.
Thanks,
Aravind
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